(1/6)^x-4=36^x

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Solution for (1/6)^x-4=36^x equation: 



(1/6)^x-4=36^x

We move all terms to the left:

(1/6)^x-4-(36^x)=0



Domain of the equation: 6)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/6)^x-36^x-4=0

We multiply all the terms by the denominator


(+1-36^x*6)^x-4*6)^x=0

Wy multiply elements

(+1-36^x*6)^x-24x=0

We add all the numbers together, and all the variables

-24x+(+1-36^x*6)^x=0

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